In non-competitive inhibition, where is the pivot point located on the graph?

Study for the ACS Biochemistry Exam. Explore flashcards and multiple choice questions with hints and explanations. Prepare to excel in your exam!

In non-competitive inhibition, the kinetics of enzyme activity can be represented through a Lineweaver-Burk plot (double reciprocal plot). The characteristic feature of non-competitive inhibition is that the inhibitor binds to an enzyme regardless of whether the substrate is bound. This leads to a decrease in the maximum reaction rate (Vmax) while the affinity of the enzyme for the substrate, represented by the Michaelis constant (Km), remains unchanged.

On a Lineweaver-Burk plot, which plots 1/V0 (the inverse of the initial velocity) on the y-axis versus 1/[S] (the inverse of the substrate concentration) on the x-axis, the y-intercept indicates the value of 1/Vmax. Since non-competitive inhibitors decrease Vmax without affecting Km, the pivot point—where the slope of the Lineweaver-Burk plot changes due to the inhibition—is not dependent on changing the x-intercept (which relates to Km). Instead, the alteration primarily affects the y-axis, where we see a shift that represents the decreased Vmax.

Therefore, identifying the pivot point on the y-axis aligns with the understanding that non-competitive inhibition primarily impacts the maximum rate of the enzymatic reaction while keeping the enzyme's affinity

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy